2x^2-6x+9=9/2

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Solution for 2x^2-6x+9=9/2 equation:



2x^2-6x+9=9/2
We move all terms to the left:
2x^2-6x+9-(9/2)=0
We add all the numbers together, and all the variables
2x^2-6x+9-(+9/2)=0
We get rid of parentheses
2x^2-6x+9-9/2=0
We multiply all the terms by the denominator
2x^2*2-6x*2-9+9*2=0
We add all the numbers together, and all the variables
2x^2*2-6x*2+9=0
Wy multiply elements
4x^2-12x+9=0
a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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